OpenXmlPackage.getContentType(uri)
Return to the
Open XML SDK for JavaScript
Developer CenterGets the content type of a part at the specified uri.
Syntax
var contentType = OpenXmlPackage.getContentType(uri);
Arguments
uri: An string that contains the uri of the part for which you want to get the content type.
Return Value
Returns a string that contains the content type of the part. If there is no part at the specified uri, this function returns null.
Usage
var contentType = OpenXmlPackage.getContentType("\word\document.xml");
Example
// Open a blank document that is stored as a base64 string. var doc = new openXml.OpenXmlPackage(blankDocument_base64); // Get the content type of the main document part. var contentType = doc.getContentType("/word/document.xml"); o = ["Content type of the main document part:", contentType]; return { output: o };