OpenXmlPart.getPartsByContentType(contentType)

Return to the
Open XML SDK for JavaScript
Developer CenterGets an array of parts that are targets of relationships from this part, and have the specified content type. openXml.contentTypes contains a list of the most common content types.

Syntax

    var parts = OpenXmlPart.getPartsByContentType(contentType);

Arguments

    contentType: An string that contains the content type.

Return Value

    Returns an array of OpenXmlPart objects. If there are no parts with the specified content type, this function returns a zero length array.

Usage

    var parts = doc.mainDocumentPart()
        .getPartsByContentType(openXml.contentTypes.styleDefinitionsPart);

Example

// Open a blank document that is stored as a base64 string.
var doc = new openXml.OpenXmlPackage(blankDocument_base64);
// Get the main document part.
var mainPart = doc.mainDocumentPart();
var parts = mainPart.getPartsByContentType(openXml.contentTypes.styles);
o = ["Number of parts: " + parts.length];
for (var i = 0; i < parts.length; i++) {
    o.push("Part #" + (i + 1).toString() + " uri: " + parts[i].uri);
}
// Note that there are convenience functions that retrieve the most commonly used parts.
var parts2 = doc.mainDocumentPart().styleDefinitionsPart();
if (parts2 != null)
    o.push("doc.mainDocumentPart().styleDefinitionsPart() also found the style definitions part");
return { output: o };